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Line symmetry: eight exercises with drawn solutions

Eight line-symmetry exercises for first-year middle school, with clear drawings and illustrated solutions: segments, triangles, four letters and coordinates.

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Line symmetry: eight exercises with drawn solutions

12 min

A line reflection flips a shape across a line, as a mirror does. To find the image of a point, go at right angles to the line and place the image the same distance beyond it. A point on the mirror line does not move. The first exercises need only a ruler and square paper; the last two use coordinates as an extra challenge.

The mirror rule

Work with one point at a time: identify the mirror line, reach it at a right angle, measure the distance and repeat it on the other side. Call the image of A “A′”. Join the new corners in the same order only after finding them all. Try the drawing before opening its solution.

1. Segment AB and the sloping line r

Draw the reflection of segment AB in line r. Find A′ and B′ first: simply sliding the segment to the right is not enough.

Segment AB lies to the left of a sloping line r; the space on the other side is empty.
Task: reflect both endpoints of the segment.
Open the solution drawing

From A and B, draw perpendiculars to r. Continue each beyond r by the same distance to find A′ and B′. Join them to obtain the reflected segment.

Segment A′B′ lies beyond the sloping line r; dashed lines join the corresponding points.
Solution: A and A′, B and B′ are equally far from r.

2. The triangle resting on line r

Copy triangle ABC onto square paper and reflect it in horizontal line r. Notice that B and C already lie on the line.

Triangle ABC is above horizontal line r; its base corners B and C lie on the line.
Task: complete the triangle below r.
Open the solution drawing

B and C stay put: B′=B and C′=C. A is three squares above r, so place A′ three squares below r in the same column. Join A′ to B and C.

The yellow triangle above r and the green triangle below r share base BC; A and A′ are vertically aligned.
Solution: the base stays on the mirror; only corner A moves.

3. Segment CD and the y-axis

Plot C(3, −2) and D(2, 1), then join them. Reflect segment CD in the y-axis and write the new coordinates.

On a coordinate grid, segment CD with C(3, −2) and D(2, 1) lies right of the y-axis.
Task: find the images of both endpoints.
Open the solution drawing

Reflection in the y-axis changes only the sign of the first coordinate: C′=(−3, −2) and D′=(−2, 1). The second coordinate stays unchanged, so each pair lies on the same row.

Segment C′D′ lies left of the y-axis, with C′=(−3, −2) and D′=(−2, 1).
Solution: C′=(−3, −2) and D′=(−2, 1).

4. Four letters, four lines: L, V, T and K

Reflect each letter in its own line: L in l (vertical), V in v (horizontal), T in t (downward-sloping), and K in k (upward-sloping). These are four separate drawings.

Four grid panels show L with vertical line l, V with horizontal line v, T with diagonal line t and K with diagonal line k; the reflected letters are missing.
Task: complete all four panels, not just the L.
Open the solution drawing

For L and V, count squares horizontally and vertically respectively. For T and K, draw a perpendicular from each corner to its sloping mirror line and repeat the distance beyond it. L faces the other way, V turns upside down, and T and K flip in their own lines.

All four panels show in green the reflected L, V, T and K, each across its own line l, v, t or k.
Complete solution: four letters and four different reflections.

5. A quadrilateral and line s

Draw a quadrilateral ABCD like the example and reflect it in sloping line s.

Concave quadrilateral ABCD lies on one side of sloping line s; the opposite side is empty.
Task: find A′, B′, C′ and D′.
Open the solution drawing

Reflect the four corners separately using perpendiculars to s and equal distances. Join A′, B′, C′ and D′ in that order. The quadrilateral keeps its shape and size but is flipped.

Matching quadrilaterals lie on opposite sides of sloping line s; dashed lines connect the four pairs of corners.
Solution: four corners, four images, then four sides.

6. Match the reflected points

In the diagram with line s, which points are the images of A, B, C, D and E? Pay attention to points that already lie on the line.

Points A, B, C and D lie below s; E and P lie on the line; K, L, R, N, O, Q, M and F appear above it.
Task: match reflected points without being distracted by the others.
Open the solution drawing

The matching pairs are A↔K, B↔N, C↔O and D↔F. E lies on s, so E↔E. P is also on the line and would stay put, but it is not among the requested points. L, R, Q and M are distractors.

Dashed lines join A to K, B to N, C to O and D to F across line s; E remains on the line.
Solution: A→K, B→N, C→O, D→F, E→E.

7. The triangle and the line through O and P(1, 3)

On a coordinate grid, draw line s through O=(0, 0) and P(1, 3). Draw triangle OAB with A(4, 2) and B(3, −1), then reflect it in s. What are its new corners?

Coordinate grid with line s through O and P(1, 3) and triangle OAB with A(4, 2), B(3, −1).
Task: reflect the triangle in line s.
Open the solution drawing

O lies on s and stays put. Drawing perpendiculars to s gives A′=(−2, 4) and B′=(−3, 1). Check: AA′ and BB′ are perpendicular to s, and their midpoints lie on s.

The reflected triangle OA′B′ lies on the other side of s, with A′=(−2, 4), B′=(−3, 1) and O unchanged.
Solution: O′=O, A′=(−2, 4), B′=(−3, 1).

8. Two triangles: find the mirror line

Draw ABC with A(1, 1), B(1, 4), C(5, 1) and DEF with D(−1, −1), E(−1, −5), F(−4, −1). Compare side lengths and find the line in which one triangle reflects into the other.

Coordinate grid with ABC at A(1, 1), B(1, 4), C(5, 1) and DEF at D(−1, −1), E(−1, −5), F(−4, −1), without a mirror line.
Task: measure the sides and draw the mirror line.
Open the solution drawing

ABC has side lengths 3, 4 and 5 units; DEF has the same lengths. The matches are A↔D, B↔F and C↔E. The mirror line is y=−x: reflecting (x, y) in it gives (−y, −x).

The triangles ABC and DEF have equal matching sides; diagonal line y=−x is their mirror, pairing A–D, B–F and C–E.
Solution: side lengths 3, 4 and 5; A↔D, B↔F, C↔E; mirror line y=−x.

What to check

A point and its image are on a line perpendicular to the mirror and are equally far from it. Reflected shapes have the same side lengths even though they look flipped. If the mirror passes through a point, that point is its own image.